Sage Of The Arctic
Stephanie Dalquist, Sam Kendig
ACID EATERS: He
Acid dissociation equilibrium problem. Ka=1.76E-5, concentration = 5.69 M, Ka=[H+][Ac]/[HAc]. Species [ ]o change[ ] equilibrium [ ] HAc 5.69 -x 5.69-x H+ 0 +x +x Ac- 0 +x +x x ends up being 0.01, so the pH of the solution is 2, or Helium.
PUMP UP THE VOLUME: Ra
PV=nRT. nR*(T1/P1 - T2/P2)=13.80 mol*0.08206Latm/molK*(273K/1atm-293K/1.5atm)=deltaV= 88L
IRON MAIDEN: S
The reaction being cued is thermite, 2Al(s)+Fe2O3(s) -> Al2O3(s)+2Fe(s) 3835.2 grams Fe2O3 = 24 moles, 446.4 g Al = 16 moles. 16 moles of Aluminum will be used, so 8 moles of Fe2O3 will be used, and 16 moles will be left over.
MEN AT WORK: He
Thermo, cycles, ideal gas. Keep in mind it's adiabatic. w=-2.03 MJ on gas or 2 by gas, so 2, or He.
SERENADE: I
This can be solved from the combustion functions and deltaH's, which can be looked up: Cgraphite(s)+O2(g) -> CO2(g) deltaH=-393.5kJ Cdiamond(s)+O2(g) -> CO2(g) deltaH=-395.4kJ Hess' Law: Cgraphite(s)+O2(g) -> COs(g) deltaH=-393.5kJ CO2(g) -> Cdiamond(s)+O2(g) deltaH=-(-395.4)kJ Cgraphite(s) -> Cdiamond(s) deltaH=1.9kJ PER MOLE The problem is for 335 grams, or 27.85 moles. Energy required is 53 kilojoules.
NEW RADICALS: F
The compound is triphenylmethyl and there are ten resonance structures, e.g. 9 more than the one shown.
VAPOR TRAILS: Er
This is a Clausius-Clayperon problem: ln(P2/P1)=deltaHvap/R*(1/T2-1/T1) ln(23.8/x)=(43900 J/mol)/(8.3145 J/Kmol)(1/316.77-1/298) Pressure = 68 torr.
AS AN ASIDE:
The names of the puzzles are not part of the solution, but are thematic to the chemistry problem. They are: