Scalar (relativity)

In relativity, a scalar is a number that is the same in all reference frames. In particular, the inner product of two vectors is a scalar.

ab=aibi=scalar. a \cdot b = a_i b^i = \text{scalar}.

This implies several things about how we represent vectors in relativity. In particular, our usual idea of a dot product will not work. Instead, we will require an inner product to be between an up and a down vector, which are related by the metric of spacetime.

Given an up vector aia^i, we write the down vector aia_i as

ai=(a0a1a2a3). a_i = \mat{-a^0 & a^1 & a^2 & a^3}.

This particularly simple form works only in special relativity in cartesian coordinates.

The negative sign allows us to say that all inner products are scalars. For example, the vector magnitude aiaia_i a^i is a scalar, and therefore an invariant.

Invariant interval

The distance between two events AA and BB in sapcetime, defined as Δs2=AB2\Delta s^2 = |A - B|^2, is called the invariant interval. Being a vector magnitude, it is invariant, and it’s value tells us what kind of separation the two events have.

If Δs2<0\Delta s^2 < 0, the c2Δt2-c^2 \Delta t^2 term dominates, and the events have a “time like” separation. There exists a reference frame in which A,BA,B occur at the same point. In this case a signal with speed v<cv < c can connect them.

If Δs2>0\Delta s^2 > 0, the distance in space dominates and the events are “space like” separated. There exists a reference frame in which A,BA,B are simultaneous. Δs=Δs2\Delta s = \sqrt{\Delta s^2} is the “proper separation” in that frame. There also exist frames where A,BA,B happen in different orders.

If Δs2=0\Delta s^2 = 0, the space and time differences cancel and the events are “light like” separated. Since cΔt=Δx2+Δy2+Δz2c \Delta t = \sqrt{\Delta x^2 + \Delta y^2 + \Delta z^2}, the events can be connected by a light pulse.

The graphic below shows the characterization of the invariant interval between the event at the middle of the light cone and the other points.