Piecewise constant potential
We can analytically find the energy eigenstates for a piecewise constant potential. Consider one constant interval, with potential V1. From the time independent Schrodinger equation, we have
Eψ1(x)∂x2∂2ψ=−2mℏ2∂x2∂2ψ1+V1ψ1(x)=−ℏ22m(E−V1)ψ1(x).We see that if E>V1, the second derivative of ψ1 is a negative constant times ψ1. This gives us a complex exponential solution ψ1=Aeikx+Be−ikx where k2=ℏ22m(E−V1).
If E<V1, then the second derivative is a positive constant times ψ1, giving us a real exponential solution ψ1=Aeκx+Be−κx.
At steps in the potential, we have the condition that both ψ and ψ′ be continuous.
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