A damped oscillator has some velocity-dependent friction force F=−Γx˙. In general, its equation of motion is:
x¨+Γx˙+ω02x=0.
We solve this by guessing x=Re[z] where z=Aeiαt.
Then
(−α2+iαΓ+ω02)Aeiαtα2−iαΓ−ω02=0=0.
Then solve for α using the quadratic formula.
α=2iΓ±−4Γ2+ω02.
Define ω=−4Γ2+ω02. Then the solution for z is:
z(t)=Ae−2Γte±iωt.
The solution for x will depend on the specific damping regime.
Damping regimes
There are three damping regimes depending on the sign of ω. In other words, if the roots of α are real or complex.
Underdamped
When ω02>Γ2/4, the oscillations are stronger than the damping. In this case the discriminant is positive and α has real roots. An underdamped oscillator may oscillate for some time before damping out.
The solution for an underdamped oscillator is:
x(t)=Re[z(t)]=e−2Γt(Acos(ωt)+Bsin(ωt)).
Or alternatively:
x(t)=Ae−2Γtcos(ωt+ϕ).
Overdamped
When ω02<Γ2/4, the damping is stronger than the oscillations. In this case the discriminant is negative and α has complex roots.
We rewrite α=i(2Γ±4Γ2−ω02). Define Γ±=2Γ±4Γ2−ω02.
Then our solution is:
x(t)=Re[Aei⋅iΓ++ei⋅iΓ−]=Ae−Γ++Be−Γ−.
Note that there is no oscillation.
Critically damped
Critically damped means ω02=Γ2/4. In this case the descriminant is 0, so x(t)=Ae−2Γt. However, since this has only one free variable it cannot be the full solution to the second-order equation. The full solution is:
x(t)=(A+Bt)e−2Γt.
A critically damped oscillator will return to equilibrium the fastest.