Covariant derivative

The partial derivative of a vector αVβ\partial_\alpha V^\beta does not transform like a tensor. The covariant derivative αVβ\nabla_\alpha V^\beta does, and is the generalization of the partial derivative to curved spacetime. It is defined in terms of the Christoffel connection. Conceptually, it takes into account the variation of the basis vectors over the manifold.

μVν=μVν+ΓμλνVλ. \begin{align*} \nabla_\mu V^\nu = \partial_\mu V^\nu + \Gamma^\nu_{\mu\lambda} V^\lambda. \end{align*}

It is simple to show that the covariant derivative transforms like a tensor. Let Lμν=xμxνL^\mu{}_\nu = \frac{\partial x^\mu}{\partial x^\nu}. Then for μVν\nabla_\mu V^\nu to be a tensor, we demand

μVν=μVν+ΓμλνVλ=LμμLννμVν=LμμLννμVν+LμμVνμLνν+ΓμλνLλλVλ=LμμLννμVν+LμμLννΓμλνVλLμμLννΓμλνVλ=ΓμλνLλλVλ+LμμVλμLννΓμλν=LμμLλλLννΓμλν+LμμLλλμLνλ. \begin{align*} \nabla_{\mu'}V^{\nu'} &= \partial_{\mu'} V^{\nu'} + \Gamma^{\nu'}_{\mu'\lambda'} V^{\lambda'} = L^\mu{}_{\mu'} L^{\nu'}{}_\nu \nabla_\mu V^\nu \\ &= L^\mu{}_{\mu'} L^{\nu'}{}_\nu \partial_\mu V^\nu + L^\mu{}_{\mu'} V^\nu \partial_\mu L^{\nu'}{}_\nu + \Gamma^{\nu'}_{\mu'\lambda'} L^{\lambda'}{}_\lambda V^\lambda \\ &= L^\mu{}_{\mu'} L^{\nu'}{}_\nu \partial_\mu V^\nu + L^\mu{}_{\mu'} L^{\nu'}{}_\nu \Gamma^\nu_{\mu\lambda} V^\lambda \\ L^\mu{}_{\mu'} L^{\nu'}{}_\nu \Gamma^\nu_{\mu\lambda} V^\lambda &= \Gamma^{\nu'}_{\mu'\lambda'} L^{\lambda'}{}_{\lambda} V^\lambda + L^\mu{}_{\mu'} V^\lambda \partial_\mu L^{\nu'}_\nu \\ \Gamma^{\nu'}_{\mu'\lambda'} &= L^\mu{}_{\mu'} L^\lambda{}_{\lambda'} L^{\nu'}{}_{\nu} \Gamma^\nu_{\mu\lambda} + L^{\mu}{}_{\mu'} L^\lambda{}_{\lambda'} \partial_\mu L^{\nu'}{}_{\lambda}. \end{align*}

The Christoffel symbol Γ\Gamma is defined such that its transformation perfectly cancels out the aditional terms introduced by the partial derivative.