Covariant derivative

The partial derivative of a vector ∂αVβ\partial_\alpha V^\beta does not transform like a tensor. The covariant derivative ∇αVβ\nabla_\alpha V^\beta does, and is the generalization of the partial derivative to curved spacetime. It is defined in terms of the Christoffel connection. Conceptually, it takes into account the variation of the basis vectors over the manifold.

∇μVν=∂μVν+ΓμλνVλ. \begin{align*} \nabla_\mu V^\nu = \partial_\mu V^\nu + \Gamma^\nu_{\mu\lambda} V^\lambda. \end{align*}

It is simple to show that the covariant derivative transforms like a tensor. Let Lμν=∂xμ∂xνL^\mu{}_\nu = \frac{\partial x^\mu}{\partial x^\nu}. Then for ∇μVν\nabla_\mu V^\nu to be a tensor, we demand

∇μ′Vν′=∂μ′Vν′+Γμ′λ′ν′Vλ′=Lμμ′Lν′ν∇μVν=Lμμ′Lν′ν∂μVν+Lμμ′Vν∂μLν′ν+Γμ′λ′ν′Lλ′λVλ=Lμμ′Lν′ν∂μVν+Lμμ′Lν′νΓμλνVλLμμ′Lν′νΓμλνVλ=Γμ′λ′ν′Lλ′λVλ+Lμμ′Vλ∂μLνν′Γμ′λ′ν′=Lμμ′Lλλ′Lν′νΓμλν+Lμμ′Lλλ′∂μLν′λ. \begin{align*} \nabla_{\mu'}V^{\nu'} &= \partial_{\mu'} V^{\nu'} + \Gamma^{\nu'}_{\mu'\lambda'} V^{\lambda'} = L^\mu{}_{\mu'} L^{\nu'}{}_\nu \nabla_\mu V^\nu \\ &= L^\mu{}_{\mu'} L^{\nu'}{}_\nu \partial_\mu V^\nu + L^\mu{}_{\mu'} V^\nu \partial_\mu L^{\nu'}{}_\nu + \Gamma^{\nu'}_{\mu'\lambda'} L^{\lambda'}{}_\lambda V^\lambda \\ &= L^\mu{}_{\mu'} L^{\nu'}{}_\nu \partial_\mu V^\nu + L^\mu{}_{\mu'} L^{\nu'}{}_\nu \Gamma^\nu_{\mu\lambda} V^\lambda \\ L^\mu{}_{\mu'} L^{\nu'}{}_\nu \Gamma^\nu_{\mu\lambda} V^\lambda &= \Gamma^{\nu'}_{\mu'\lambda'} L^{\lambda'}{}_{\lambda} V^\lambda + L^\mu{}_{\mu'} V^\lambda \partial_\mu L^{\nu'}_\nu \\ \Gamma^{\nu'}_{\mu'\lambda'} &= L^\mu{}_{\mu'} L^\lambda{}_{\lambda'} L^{\nu'}{}_{\nu} \Gamma^\nu_{\mu\lambda} + L^{\mu}{}_{\mu'} L^\lambda{}_{\lambda'} \partial_\mu L^{\nu'}{}_{\lambda}. \end{align*}

The Christoffel symbol Γ\Gamma is defined such that its transformation perfectly cancels out the aditional terms introduced by the partial derivative.