As defined on p. 111 of your text, the axis of symmetry of a parabola is the vertical line down its center; the parabola has mirror symmetry across the line of the axis of symmetry. The vertex is the point where the axis of symmetry intersects the parabola; it represents either a maximum or minimum value of the quadratic function whose graph is the parabola.
For instance, the quadratic function f(x) = x2 - 1 whose graph
is shown on the left below has the axis of symmetry x=0 and vertex (0,-1).
The quadratic function g(x) = x^2 whose graph is shown on page 55 of
your text has axis of symmetry x=0 and vertex (0,0). Since f(x) + 1 =
g(x), this should be no surprise; adding 1 to the output of f(x)
shifts the graph, and the vertex, upward by 1 unit. Similarly, if we
define a function h(x) = f(x-2) = (x-2)2 - 1 =
x2 - 4x + 3 will have the same graph as that of f(x) only
shifted 2 units to the right; its axis of symmetry will be x=2 and its
vertex will be at (2,-1). The graph of F(x) = 2(f(x)) =
2x2 - 2, shown on the right above, has the same axis of
symmetry as that of f(x). However, multiplying the output of f(x) by
2 has "stretched" the graph vertically so that the vertex of F(x) is
at (0,-2) and the parabola falls and rises more steeply.
Use reasoning similar to the examples given above and used in section 1.6 of your text to fill in the properties of the graphs of functions in the table below. Use a graphing calculator or Graphmatica to check your work.
Function | Vertex | Opens up/down | Stretched? |
f1(x) = x2 | |||
f2(x) = x2 + 3 | |||
f3(x) = x2 + k | |||
g1(x) = (x - 2)2 | |||
g2(x) = (x - 2)2 + 3 | |||
g3(x) = (x - h)2 | |||
g4(x) = (x - h)2 + k | |||
g4(x) = (x - h)2 + k | |||
f4(x) = -x2 | |||
f5(x) = 42 | |||
f6(x) = 4(x - 2)2 + 3 | |||
f7(x) = -4(x - 2)2 + 3 | |||
f8(x) = a(x - h)2 + k | |||