Written by Sofiya Vasina
The solution to the cross sum is not quite unique; in
5487961
32 352 39
51 79 58
7986 62 3268
17 4 9 1 79
58 362 32 364
1 5
312 23 249 97
89 4 4 5 86
4..3 23 3125
.. 61 89
62 857 68
9861547
one can replace the two-by-two square of dots above with either
87 78 76 or 85
to obtain a valid solution. In either case, if we "look out for 2 3" as instructed, we find that the 2's and 3's form the following pattern (using # for 2 and 3 and . for all other numbers):
.......
## # # #.
.. .. ..
.... .# ##..
.. . . . ..
.. #.# ## #..
. .
#.# ## #.. ..
.. . . . ..
...# ## #.#.
.. .. ..
.# ... ..
.......
Interpreting # as "dot" and ## as "dash" and reading each row with #'s in it as a Morse Code letter, this gives us the solution, BAFFLE.